Nugroho's blog.: PI on MPI

Thursday, May 2, 2013

PI on MPI

still trying...
 program main
include "mpif.h"
double precision PI25DT
parameter (PI25DT = 3.141592653589793238462643d0)
double precision mypi, pi, h, sum, x, f, a
integer n, myid, numprocs, i, ierr
c function to integrate
f(a) = 4.d0 / (1.d0 + a*a)

call MPI_INIT(ierr)
call MPI_COMM_RANK(MPI_COMM_WORLD, myid, ierr)
call MPI_COMM_SIZE(MPI_COMM_WORLD, numprocs, ierr)


10 if ( myid .eq. 0 ) then
print *, 'Enter the number of intervals: (0 quits) '
read(*,*) n
endif
c broadcast n
call MPI_BCAST(n,1,MPI_INTEGER,0,MPI_COMM_WORLD,ierr)
c check for quit signal
if ( n .le. 0 ) goto 30
c calculate the interval size
h = 1.0d0/n
sum = 0.0d0
do 20 i = myid+1, n, numprocs
x = h * (dble(i) - 0.5d0)
sum = sum + f(x)
20 continue
mypi = h * sum
c collect all the partial sums
call MPI_REDUCE(mypi,pi,1,MPI_DOUBLE_PRECISION,MPI_SUM,0,
& MPI_COMM_WORLD,ierr)
c node 0 prints the answer.
if (myid .eq. 0) then
print *, 'pi is ', pi, ' Error is', abs(pi - PI25DT)
endif
goto 10
30 call MPI_FINALIZE(ierr)
stop
end

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